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Less Recoil Source Code

Posts 1–15 of 26 · Page 1 of 2

GUYS...i have tryed and tryed and tryed for about 4 days to find NoRecoil text string but i cant find it i only know 3 which is BulletPosOffset and loweranimerate and Crosshairratioperrealsize smthing like that/.... but it only make Less Recoil I will show my code...with a little antileechprotect

any way for those who will say U need 45-50 offsets Tell me the text string or how to find it..for those who say learn asm or C++ **** U...

Code:

#include "stdafx.h"

#define WeaponMgr 0xA68F90
#define recoil1 0x1928
#define recoil2 0x192C
#define recoil3 0x1930
#define recoil4 0x2520 
#define recoil5 0x258C
#define recoil6 0x2590
#define recoil7 0x2594
#define recoil8 0x26A4


DWORD WINAPI Hacks(LPVOID)
{
bool recoil = true; 


while(1)
{
DWORD CShell = (DWORD)GetModuleHandleA("CShell.dll");
DWORD pWeaponMgr = *(DWORD*)(CShell+WeaponMgr);


if (recoil)

if (pWeaponMgr)

for(int i=0; i<560; i++)
{
if((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr))+(4*i)) ) != NULL)
{
for (int j=0; j<9 ; j++)
{
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x192C+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaonMgr)) +(4*i))) + 0x1928+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x1930+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2520+j*4) = 0.0f;
*(float*)((*(DORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x258C+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2590+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2594+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x26A4+j*4) = 0.0f;
}


}
}
Sleep(100);


}
}

bool Ready2Hook()
{
if(GetModuleHandleA("CShell.dll") != NULL
&& GetModuleHandleA("ClientFx.fxd") != NULL)
return 1;
return 0;
}

DWORD WINAPI Wait(LPVOID)
{
while(!Ready2Hook()) Sleep(200);
CreateThread(NULL, NULL, (LPTHREAD_START_ROUTINE)Hacks, NULL, NULL, NULL);
return 0;
}

BOOL WINAPI DllMain ( HMODULE hDll, DWORD dwReason, LPVOID lpReserved )
{
DisableThreadLibraryCalls(hDll);

if ( dwReason == DLL_PROCESS_ATTACH )
{

MessageBoxA(0, "Credits- devil","ghost", 0);


CreateThread(0,0,(LPTHREAD_START_ROUTINE)Wait,0,0, 0);
}
return 1;
}

PS : FOR THOSE WHO WILL SAY ANYTHING ABOUT THE CODE....I PUT THE ANTILEECHPROTECT..AND I KNOW IT'S SWIFTDUDE'S

IT'S SWIFTDUDE'S

Sorry, but I can't read text as big as that.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

next goal: full no recoil

too easy >.<

i know it xd

Originally Posted by Ghost Rider.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

I already tryed...doesnt differ..

Originally Posted by Brimir

IT'S SWIFTDUDE'S

Sorry, but I can't read text as big as that.

Lol good joke...

Why use Less Recoil , if Ghost Rider post Perfect NoRecoil ?

Originally Posted by LoveyMush

Why use Less Recoil , if Ghost Rider post Perfect NoRecoil ?

I want to do it my self

yeah ? , Good Luck for you !!

Take the offsets and search for Constant , and you can see the strings , if you can search strings you can update the offsets if Z8 patch

@LoveyMush

:O , thaank you , i find the strings now ! haha thank you love

Originally Posted by Ghost Rider.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

50%
It doesnt matter if you interger j or y. It is just a variable. Lower the loop only

Maybe its C+P :/

Originally Posted by oicaradeboi

Maybe its C+P :/

LOL what is C+P??

i looked 2 seconds over this code.. i read only this code part > and its extremely false!

Code:

2C+j*4) = 0.0f;

fail code! fail thopic! sory.. but lol

edit// becouse the offs is not 4*loop :P .. just and only fail coders here!
edit 2 // only the wep pointer is 4*loop

Posts 1–15 of 26 · Page 1 of 2

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Home › Forum › MultiPlayer Game Hacks & Cheats › CrossFire Hacks & Cheats › CrossFire Hack Coding / Programming / Source Code › Less Recoil Source Code

Less Recoil Source Code

Posts 1–15 of 26 · Page 1 of 2

Less Recoil Source Code

any way for those who will say U need 45-50 offsets Tell me the text string or how to find it..for those who say learn asm or C++ **** U...

Code:

#include "stdafx.h"

#define WeaponMgr 0xA68F90
#define recoil1 0x1928
#define recoil2 0x192C
#define recoil3 0x1930
#define recoil4 0x2520 
#define recoil5 0x258C
#define recoil6 0x2590
#define recoil7 0x2594
#define recoil8 0x26A4


DWORD WINAPI Hacks(LPVOID)
{
bool recoil = true; 


while(1)
{
DWORD CShell = (DWORD)GetModuleHandleA("CShell.dll");
DWORD pWeaponMgr = *(DWORD*)(CShell+WeaponMgr);


if (recoil)

if (pWeaponMgr)

for(int i=0; i<560; i++)
{
if((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr))+(4*i)) ) != NULL)
{
for (int j=0; j<9 ; j++)
{
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x192C+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaonMgr)) +(4*i))) + 0x1928+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x1930+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2520+j*4) = 0.0f;
*(float*)((*(DORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x258C+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2590+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x2594+j*4) = 0.0f;
*(float*)((*(DWORD*)((*(DWORD*)(CShell+WeaponMgr)) +(4*i))) + 0x26A4+j*4) = 0.0f;
}


}
}
Sleep(100);


}
}

bool Ready2Hook()
{
if(GetModuleHandleA("CShell.dll") != NULL
&& GetModuleHandleA("ClientFx.fxd") != NULL)
return 1;
return 0;
}

DWORD WINAPI Wait(LPVOID)
{
while(!Ready2Hook()) Sleep(200);
CreateThread(NULL, NULL, (LPTHREAD_START_ROUTINE)Hacks, NULL, NULL, NULL);
return 0;
}

BOOL WINAPI DllMain ( HMODULE hDll, DWORD dwReason, LPVOID lpReserved )
{
DisableThreadLibraryCalls(hDll);

if ( dwReason == DLL_PROCESS_ATTACH )
{

MessageBoxA(0, "Credits- devil","ghost", 0);


CreateThread(0,0,(LPTHREAD_START_ROUTINE)Wait,0,0, 0);
}
return 1;
}

PS : FOR THOSE WHO WILL SAY ANYTHING ABOUT THE CODE....I PUT THE ANTILEECHPROTECT..AND I KNOW IT'S SWIFTDUDE'S

IT'S SWIFTDUDE'S

Sorry, but I can't read text as big as that.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

next goal: full no recoil

too easy >.<

i know it xd

Originally Posted by Ghost Rider.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

I already tryed...doesnt differ..

Originally Posted by Brimir

IT'S SWIFTDUDE'S

Sorry, but I can't read text as big as that.

Lol good joke...

Why use Less Recoil , if Ghost Rider post Perfect NoRecoil ?

Originally Posted by LoveyMush

Why use Less Recoil , if Ghost Rider post Perfect NoRecoil ?

I want to do it my self

yeah ? , Good Luck for you !!

Take the offsets and search for Constant , and you can see the strings , if you can search strings you can update the offsets if Z8 patch

@LoveyMush

:O , thaank you , i find the strings now ! haha thank you love

Originally Posted by Ghost Rider.

Your loop (int j=0; j<10; j++)
change to (int y = 0; y <9; y++)

50%
It doesnt matter if you interger j or y. It is just a variable. Lower the loop only

Maybe its C+P :/

Originally Posted by oicaradeboi

Maybe its C+P :/

LOL what is C+P??

i looked 2 seconds over this code.. i read only this code part > and its extremely false!

Code:

2C+j*4) = 0.0f;

fail code! fail thopic! sory.. but lol

edit// becouse the offs is not 4*loop :P .. just and only fail coders here!
edit 2 // only the wep pointer is 4*loop

Posts 1–15 of 26 · Page 1 of 2

Post a Reply

Similar Threads

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25Last post 15y ago
Can i Have No Recoil Source Code..? I'm almost done my first release for MPGHBy topgenral in CrossFire Hack Coding / Programming / Source Code
12Last post 14y ago
How to Edit a files source Code to change so that it is less detectableBy zakodia in Call of Duty Modern Warfare 2 Help
5Last post 16y ago
[Release] WarHax DLL Source CodeBy OneWhoSighs in WarRock - International Hacks
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Tags for this Thread

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