time delay to the moon
time delay to the moon
in my tutorial was a program to calculate the time delay to the mars.
the output is:
Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.
now i wanted to make to look like this:
Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:
but it didn't work out so how can i make it work?
edit: oops wrong title i mean mars. xD
the output is:
Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.
now i wanted to make to look like this:
Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:
but it didn't work out so how can i make it work?
#include <iostream>
using namespace std;
int main ()
{
double distance, lightspeed, delay, delay_in_min, seconds;
int delay_in_min_2;
/* i added int delay_in_min_2; to calculate the seconds left after the whole minutes (minutes-minutes rounded)*60 */
distance = 34000000.0;
lightspeed = 186000;
delay = distance/lightspeed;
cout << "Time delay when talking to mars: " << delay << " seconds." << endl;
delay_in_min= delay/60.0;
cout << "This is " << delay_in_min << " minutes." <<endl;
seconds = (delay_in_min-delay_in_min_2)*60;
// [Warning ] converting to int from double. how to do it else?
delay_in_min_2= ((distance/lightspeed)/60);
cout << "Time delay when talking to mars: " << delay_in_min_2 <<" minutes and " << seconds <<endl;
system ("pause");
return 0;
}
using namespace std;
int main ()
{
double distance, lightspeed, delay, delay_in_min, seconds;
int delay_in_min_2;
/* i added int delay_in_min_2; to calculate the seconds left after the whole minutes (minutes-minutes rounded)*60 */
distance = 34000000.0;
lightspeed = 186000;
delay = distance/lightspeed;
cout << "Time delay when talking to mars: " << delay << " seconds." << endl;
delay_in_min= delay/60.0;
cout << "This is " << delay_in_min << " minutes." <<endl;
seconds = (delay_in_min-delay_in_min_2)*60;
// [Warning ] converting to int from double. how to do it else?
delay_in_min_2= ((distance/lightspeed)/60);
cout << "Time delay when talking to mars: " << delay_in_min_2 <<" minutes and " << seconds <<endl;
system ("pause");
return 0;
}
Originally Posted by lalakijilp
in my tutorial was a program to calculate the time delay to the mars.
the output is:
Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.
now i wanted to make to look like this:
Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:
but it didn't work out so how can i make it work?
edit: oops wrong title i mean mars. xD
the output is:
Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.
now i wanted to make to look like this:
Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:
but it didn't work out so how can i make it work?
edit: oops wrong title i mean mars. xD
Originally Posted by zeco
Well one thing is when you first used delay_in_min_2, it wasn't given a value yet
Is this C#? Cause I tried working with it and I have a few undefined functions.
no, it is C++
this was the error.
[Warning ] converting to int from double.
i put it in the code too. hwo to do it otherwise
this was the error.
[Warning ] converting to int from double.
i put it in the code too. hwo to do it otherwise
Ah, I see almost complete with a solution. 
By the way, did you get an error about your delay_in_min_2? I had to fix it because my compiler said unknown identifier.
Ok, simply when you want your answer to be a different type place the type you want it to be in parenthensies. Ex.:
The result of this would be 10...
By the way, did you get an error about your delay_in_min_2? I had to fix it because my compiler said unknown identifier.Code:
//myfirst.cpp--displays a msg
#include <iostream>
using namespace std;
int main ()
{
double distance;
double lightspeed;
double delay;
double DelayInMin;
double seconds;
int DelayInMin2;
// I smoothed things into my own style a little =)
distance = 34000000.0;
lightspeed = 186000;
delay = distance/lightspeed;
cout << "Time delay when talking to mars: " << delay << " seconds." << endl;
DelayInMin = delay/60.0;
cout << "This is " << (int)DelayInMin << " minutes." <<endl;
DelayInMin2 = ((distance/lightspeed)/60);//You must declare the variable before using it =), or at least in my case =S
seconds = (DelayInMin-DelayInMin2)*60;
// [Warning ] converting to int from double. how to do it else?
cout << "Time delay when talking to mars: " << (int)DelayInMin2 << " minutes and " << (int)seconds << " seconds.";
cin.get();
return 0;
Code:
//This is an example =P double test = 10.56567 cout << "I will reveal to you an integer: " << (int)test;
so you can change a double to an int by putting (int) before it?
Yes and ignore the (int) I put in this line of code, it isn't required
Originally Posted by lalakijilp
so you can change a double to an int by putting (int) before it?
Also here is how I would have coded your delay calculator:
Code:
#include <iostream>
using namespace std;
int main()
{
double distance, delay;
double SoL = 186000; //miles per second
cout << "LightSpeed Delay Calculator\n" ;
cout << "Enter distance in miles: \n";
cin >> distance;
int seconds = (int)(distance/SoL);
cout << "The time delay for a distance of " << distance << " miles is " << seconds/60 << " minutes and " << seconds%60 << " second(s).";
system("pause");
return 0;
}
Well it took long enough, and got kinda confusing at times, and I could have gone about it a different way, but here is my completed version that automatically calculates years, days, hours, minutes, and seconds.
Unfortunately it breaks if you inter a value bigger then an integer can hold. It also breaks if you enter something that isn't a number. But hey this is all the effort I'm gonna put into it since I will probably never use it :P
you can compile this code and it should run.
Unfortunately it breaks if you inter a value bigger then an integer can hold. It also breaks if you enter something that isn't a number. But hey this is all the effort I'm gonna put into it since I will probably never use it :P
Code:
#include <iostream>
using namespace std;
void time(double seconds);
int main()
{
double distance, delay;
double SoL = 186000; //miles per second
cout << "LightSpeed Delay Calculator\n" ;
cout << "Enter distance in miles: \n";
cin >> distance;
delay = distance/SoL;
cout <<"The calculated time delay is: ";
time(delay);
cout<<endl ;
system("pause");
return 0;
}
// a function that will take parameters in seconds and convert to cyclical time.
void time(double seconds)
{
int minute = 60;
int hour = 3600;
int day = 3600*24;
int year = 3600*24*365;
int second = (int)seconds;
int perfectseconds = second%minute;
int perfectminutes = ((second/minute)%60);
int perfecthours = ((second/hour)%24);
int perfectdays = ((second/day)%365);
int perfectyears = (second/year);
if(seconds < year)
{
if(seconds < day)
{
if(seconds < hour)
{
if(seconds < minute)
{
cout << (int)seconds << " seconds";
}
else cout << perfectminutes << "minutes and " << perfectseconds << " seconds";
}
else cout << perfecthours << "hours " << perfectminutes << " minutes and " << perfectseconds << "seconds";
}
else cout << perfectdays << "days " << perfecthours << " hours " << perfectminutes << " minutes " << perfectseconds << "seconds";
}
else cout << perfectyears << "years " << perfectdays << " days" << perfecthours << " hours " << perfectminutes << " minutes " << perfectseconds << "seconds";
}
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