Hex Confusion....

I am very confused... To put it lightly

First i Will post a code fragment
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char bit = '\x42';
char mi = 0x42;
char f = '0x42';

cout << bit << endl << mi << endl << f << endl;
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The output to this is
My question is why....

'\x42' is B, that makes sense, the hexadecimal ascii character code for B is 0x42, and \x is the escape sequence for hexadecimal values, thus '\x42' == 0x42

0x42 is Appearently B also. This kinda makes sense, with everything i said before, but apparently even without the ' ' it is recognized as a character

'0x42' is 2...... This is where i am completely confused, why in the world is '0x42' the integer 2?

From what i know '\x42' and 0x42 should be equivalent, which it is. The last one just confounds me thought

Thanks for your time. I'm sure i'm overlooking something.

Edit: After playing with it some more, it would seem that it could just be randomly Organized Nonsense. I'd still like a definitive answer though.